Si tenemos dos funciones: f(x) y g(x), de modo que el dominio de la 2\u00aa est\u00e9 incluido en el recorrido de la 1\u00aa, se puede definir una nueva funci\u00f3n que asocie a cada elemento del dominio de f(x) el valor de g[f(x)].<\/strong><\/p>\n

$\"Explicaciones$ <\/p>\n

(g o <\/span>f) (x) = g [f(x)] = g (2x) = 3 (2x) +1 = 6x + 1<\/strong><\/p>\n

(g o<\/span> f) (1) = 6\u00b7 1 + 1 = 7 <\/p>\n

Dominio<\/h2>\n
D_{(g o <\/span>f) <\/sub> = {x D_{f <\/sub> \/ f(x) D_{g<\/sub>} <\/strong><\/p>\n}}}
Propiedades<\/h2>\n
Asociativa:<\/p>\n
f o<\/span> (g o<\/span> h) = (f o<\/span> g) o<\/span> h<\/strong><\/p>\n
No es conmutativa.<\/p>\n
f o<\/span> g \u2260 g o<\/span> f<\/strong><\/p>\n
El elemento neutro es la funci\u00f3n identidad<\/strong>, i(x) = x<\/strong>.<\/p>\n
f o<\/span> i = i o<\/span> f = f<\/strong> <\/p>\n
<\/p>\n
Sean las funciones:<\/p>\n
$\"Explicaciones$ <\/p>\n
$\"Explicaciones$ <\/p>\n
$\"Explicaciones$ <\/p>\n
$\"Explicaciones$ <\/p>\n
$\"Explicaciones$ <\/p>\n
<\/p>\n
$\"Explicaciones$ <\/p>\n
$\"Explicaciones$ <\/p>\n
$\"Explicaciones$ <\/p>\n
<\/p>\n
$\"Explicaciones$ <\/p>\n
$\"Explicaciones$ <\/p>\n
$\"Explicaciones$ <\/p>\n<\/section>\n","protected":false},"excerpt":{"rendered":"
Si tenemos dos funciones: f(x) y g(x), de modo que el dominio de la 2\u00aa est\u00e9 incluido en el recorrido de la 1\u00aa, se puede definir una nueva funci\u00f3n que asocie a cada elemento del dominio de f(x) el valor de g[f(x)]. (g o f) (x) = g [f(x)] = g (2x) = 3 (2x) […]<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_seopress_robots_primary_cat":"","_seopress_titles_title":"","_seopress_titles_desc":"","_seopress_robots_index":"","advgb_blocks_editor_width":"","advgb_blocks_columns_visual_guide":"","footnotes":""},"categories":[366],"tags":[361],"class_list":["post-109801","post","type-post","status-publish","format-standard","hentry","category-calculo","tag-f"],"acf":[],"author_meta":{"display_name":"Andra","author_link":"https:\/\/www.superprof.es\/diccionario\/author\/andra"},"featured_img":null,"coauthors":[],"tax_additional":{"categories":{"linked":["C\u00e1lculo<\/a>"],"unlinked":["C\u00e1lculo<\/span>"]},"tags":{"linked":["f<\/a>"],"unlinked":["f<\/span>"]}},"comment_count":"0","relative_dates":{"created":"Publicado 6 a\u00f1os hace","modified":"Actualizado 6 a\u00f1os hace"},"absolute_dates":{"created":"Publicado el 29 enero 2020","modified":"Actualizado el 29 enero 2020"},"absolute_dates_time":{"created":"Publicado el 29 enero 2020 18 h 14 min","modified":"Actualizado el 29 enero 2020 18 h 14 min"},"featured_img_caption":"","series_order":"","_links":{"self":[{"href":"https:\/\/www.superprof.es\/diccionario\/wp-json\/wp\/v2\/posts\/109801","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.superprof.es\/diccionario\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.superprof.es\/diccionario\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.superprof.es\/diccionario\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/www.superprof.es\/diccionario\/wp-json\/wp\/v2\/comments?post=109801"}],"version-history":[{"count":0,"href":"https:\/\/www.superprof.es\/diccionario\/wp-json\/wp\/v2\/posts\/109801\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.superprof.es\/diccionario\/wp-json\/wp\/v2\/media?parent=109801"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.superprof.es\/diccionario\/wp-json\/wp\/v2\/categories?post=109801"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.superprof.es\/diccionario\/wp-json\/wp\/v2\/tags?post=109801"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}