Averigua el valor de la variable dependiente en cada caso:
1 y = 3x + 1
x = 0 y =
x = 5 y =
x = 0 y = 3 · 0 + 1 = 0 + 1 = 1
x = 5 y = 3 · 5 + 1 = 15 + 1 = 16
21y = 4(2 − x)
x = −3 y =
x = 2 y =
x = −3 y = 4 · [2 − (−3)] = 4 · 5 = 20
x = 2 y = 4 · (2 − 2) = 4 · 0 = 0
3y = (x + 4)²
x = −6 y =
x = 6 y =
x = −5 y = (−6 + 4)² = (−2)² = 4
x = 6 y = (6 + 4)² = 10² = 100
4f(x) = 4x − 7
f(0) =
f(2) =
f(0) = 4 · 0 − 7 = 0 − 7 = −7
f(2) = 4 · 2 − 7 = 8 − 7 = 1
5f(x) = −7x + 8
f(−3) =
f(4) =
f(−3) = −7 · (−3) + 8 = 21 + 8 = 29
f(4) = −7 · 4 + 8 = −28 + 8 = −20
6f(x) = (3x − 2)³
f(0) =
f(3) =
f(0) = (3 · 0 − 2)³ = (−2)³ = −8
f(3) = (3 · 3 − 2)³ = 7³ = 343
Si tienes dudas puedes consultar la teoría
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